Torque on a Wire: Find Max & Range of Energies

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SUMMARY

The discussion focuses on calculating the maximum torque and range of potential energies for a circular wire in a magnetic field. The wire has a diameter of 10.0 cm and carries a current of 5.00 A in a uniform magnetic field of 3.00 mT. The formula used for torque is T = μ x B, where μ is the magnetic moment calculated as IA, with A being the area of the circular wire. The area is determined using the formula A = πr², leading to a maximum torque calculation of T = (5.00 A)((2π)(0.05 m)²)(3.00 mT).

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  • Ability to calculate area of a circle
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Homework Statement


A wire is formed into a circle having a diameter of 10.0 cm and placed in a uniform magnetic field of 3.00 mT. The wire carries a current of 5.00 A. Find (a) the maximum torque on the wire (b) the range of potential energies of the wire field system for different orientations of the circle.


Homework Equations



T= mu x B

The Attempt at a Solution



For part a I did: T= mu x B= IA x B= I((2pi)(.5m)^2) x B
= (5.00A)((2pi)(.5m)^2) x (3.00mT)

is this right? if not what do I need to do?

For part b: I have no idea and any help would be appreciated.
 
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Check the area of the coil.
 

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