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Torque required to stop wheel in 41.2s?

  1. Apr 3, 2012 #1
    1. The problem statement, all variables and given/known data
    A ten pound car wheel has a moment of inertia of .35 kgm^2. While rotating at a constant speed the wheel makes 87.61 revolutions in 5.42s. How much torque is required to stop the wheel in 41.2 s?


    2. Relevant equations



    3. The attempt at a solution
    87.61rev/5.42sec = 16.164 rev/sec x 2pi = 101.56 rad/s / 41.2 sec = 2.465 rad/s^2
    t= .35 kgm^2 x -.2.465 = -.8675 m x n?

    not sure how relevant all of the steps i did are but that is where i stopped... any help?
     
  2. jcsd
  3. Apr 4, 2012 #2

    tiny-tim

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    welcome to pf!

    hi 03sto! welcome to pf! :wink:

    yes, that looks ok :smile: (except, "m x n" should be "Nm" or "N.m")

    what is worrying you about it? :confused:
     
  4. Apr 4, 2012 #3
    Okay thanks for the feedback, i just figured i did it completely wrong haha. Thanks and yes i will switch the mn to nm. Thanks!
     
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