Torque required to stop wheel in 41.2s?

[03sto]

Homework Statement

A ten pound car wheel has a moment of inertia of .35 kgm^2. While rotating at a constant speed the wheel makes 87.61 revolutions in 5.42s. How much torque is required to stop the wheel in 41.2 s?

Homework Equations

The Attempt at a Solution

87.61rev/5.42sec = 16.164 rev/sec x 2pi = 101.56 rad/s / 41.2 sec = 2.465 rad/s^2
t= .35 kgm^2 x -.2.465 = -.8675 m x n?

not sure how relevant all of the steps i did are but that is where i stopped... any help?

 

[tiny-tim]

welcome to pf!

hi 03sto! welcome to pf!

yes, that looks ok (except, "m x n" should be "Nm" or "N.m")

what is worrying you about it? ​

 

[03sto]

Okay thanks for the feedback, i just figured i did it completely wrong haha. Thanks and yes i will switch the mn to nm. Thanks!