1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Torque required to stop wheel in 41.2s?

  1. Apr 3, 2012 #1
    1. The problem statement, all variables and given/known data
    A ten pound car wheel has a moment of inertia of .35 kgm^2. While rotating at a constant speed the wheel makes 87.61 revolutions in 5.42s. How much torque is required to stop the wheel in 41.2 s?

    2. Relevant equations

    3. The attempt at a solution
    87.61rev/5.42sec = 16.164 rev/sec x 2pi = 101.56 rad/s / 41.2 sec = 2.465 rad/s^2
    t= .35 kgm^2 x -.2.465 = -.8675 m x n?

    not sure how relevant all of the steps i did are but that is where i stopped... any help?
  2. jcsd
  3. Apr 4, 2012 #2


    User Avatar
    Science Advisor
    Homework Helper

    welcome to pf!

    hi 03sto! welcome to pf! :wink:

    yes, that looks ok :smile: (except, "m x n" should be "Nm" or "N.m")

    what is worrying you about it? :confused:
  4. Apr 4, 2012 #3
    Okay thanks for the feedback, i just figured i did it completely wrong haha. Thanks and yes i will switch the mn to nm. Thanks!
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Torque required to stop wheel in 41.2s?
  1. Wheel Torque (Replies: 4)

  2. Torque and wheels (Replies: 1)

  3. Torque on a wheel (Replies: 27)