Torque: Why does tension = Friction

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SUMMARY

The discussion centers on calculating the tension in a string attached to a 10.0 kg sphere on an incline. The tension (T) is determined to be 30.9 N using the equilibrium of forces and torques. The key relationship established is F = T, where F represents the force acting on the sphere. This relationship is derived by analyzing the moments about a pivot point where only the tension and the force contribute to the torque.

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  • Familiarity with trigonometric functions in physics
  • Ability to solve equilibrium equations
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  • Learn about torque calculations and their applications
  • Explore the relationship between forces on inclined planes
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anirzehc
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Homework Statement


A 10.0 kg sphere is attached to the incline by a horizontal string. Whats the tension in the string.
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Homework Equations


sum of all horizontal forces = 0
sum of all vertical forces = 0
sum of all torques = 0

The Attempt at a Solution


The sum of the horizontal forces[/B] is -Tsin55 degrees - F + mgsin35 degrees = 0
Why does F= T?
I know F= T because when I substitute F=T and solve for T I get the right answer (30 .9 N) but why is this?
 
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anirzehc said:
I know F= T because when I substitute F=T and solve for T I get the right answer (30 .9 N) but why is this?
If you want a quick way to get a relationship between F and T, the trick is to take moments about a point where only those two forces have a moment. What other forces are present? What point do none of those have a moment about?
 

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