Torque with a pulley of radius R and mass M

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SUMMARY

The discussion focuses on analyzing a system involving two masses, m1 and m2, connected by a massless string over a pulley with mass Mp and radius R. The acceleration of m1 is derived using the formula a = (m2g) / (m2 + m1), and the tension in the string is calculated as T = m1(m2g / (m2 + m1)). When considering the pulley’s mass, the equations for tension and acceleration must be adjusted to account for the pulley's moment of inertia, I, which can be approximated as that of a uniform disk.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with torque and its calculation
  • Knowledge of moment of inertia for different shapes
  • Basic algebra for solving simultaneous equations
NEXT STEPS
  • Study the concept of moment of inertia for a uniform disk
  • Learn how to derive equations of motion for systems with pulleys
  • Explore the effects of friction on pulley systems
  • Investigate the dynamics of non-massless pulleys in mechanical systems
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Physics students, mechanical engineers, and anyone studying dynamics involving pulleys and rotational motion.

holmeskaei
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Homework Statement



Blocks of mass m_1 and m_2 are connected by a massless string that passes over the pulley in the figure (Intro 1 figure) . The pulley turns on frictionless bearings, and mass m_1 slides on a horizontal, frictionless surface. Mass m_2 is released while the blocks are at rest.

http://session.masteringphysics.com/problemAsset/1073792/5/12.P71.jpg

I figured out A and B.
A. Assume the pulley is massless. Find the acceleration of m_1.
a=(m2g)/(m2+m1)
B. Find the tension in the string.
T=m1(m2g/m2+m1)
C. Suppose the pulley has mass m_p and radius R. Find the acceleration of m_1. Verify that your answers agree with part A if you set m_p=0.

D. Find the tension in the upper portion of the string. Verify that your answers agree with part B if you set m_p=0.

E.Find the tension in the lower portions of the string. Verify that your answers agree with part B if you set m_p=0.

Homework Equations


torque=Fxd
torque net=sum of all forces
T1=m1a+m1g
T2=m2a+m2g
torque net=T1r-T2r=(-a/r)I

The Attempt at a Solution


I know that the tensions change because of the mass and radius of the pulley, but I don't know what it does. I made a FBD, but I don't know what to do with my equations... I don't get it.
 
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holmeskaei said:
T1=m1a+m1g
The weight acts vertically; just consider horizontal forces on m1. (Vertical forces cancel.)
T2=m2a+m2g
Assuming "a" is a positive number, it looks like you have the signs wrong.
torque net=T1r-T2r=(-a/r)I
OK. But what's I for the pulley? (Maybe you can treat it like a uniform disk.)

Correct these equations and solve simultaneously.
 

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