Total angular momentum quantum number

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SUMMARY

The total angular momentum quantum number, J, for the electron configuration 1s2 2s2 2p2 3p1 is calculated as J = L + S. For the n=1 and n=2 states, the total angular momentum L is 0 due to the s shell configuration. In the n=2 p shell, L equals 2 from two electrons, while their spins cancel out, resulting in S = 0. For the n=3 state, with one electron in the p shell, L = 1 and S = 1/2. Thus, the total angular momentum J is computed as J = 2 + 1 + 1/2 = 7/2, confirming the calculation is correct.

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  • Understanding of quantum numbers, specifically angular momentum quantum numbers.
  • Knowledge of electron configurations and their implications on angular momentum.
  • Familiarity with the Pauli exclusion principle and electron spin.
  • Basic principles of quantum mechanics related to atomic structure.
NEXT STEPS
  • Study the implications of the Pauli exclusion principle on electron configurations.
  • Learn about the addition of angular momentum in quantum mechanics.
  • Explore the significance of total angular momentum in atomic spectroscopy.
  • Investigate the role of quantum numbers in determining electron behavior in multi-electron atoms.
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Students of quantum mechanics, physicists studying atomic structure, and anyone interested in the behavior of electrons in multi-electron systems.

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lets say there is an electron configuraiton of [tex]1s^2 2s^2 2p^2 3p^1[/tex]

I want to find the total angular momentum quantum number, J=L+S

considering the n=1 state, there are two electrons, in the s shell which means one is spin 1/2 and the other is spin -1/2 giving a total spin of 0. The s shell has no angular momentum so L=0.

considering n=2 state, there are two electrons in the s shell which again gives us 0 total angular momentum. If we went to the p shell, there are 2 electrons in the p shell, each having L=1, so we add them together to get L=2. The two electrons do not contribute spin since their net sum is zero, S=1/2-1/2=0.

considering the n=3 state, there is 1 electron in the p shell, which means S=1/2 and L=1

J is the sum of L and S, so the total angular momentum should be J=L+S=2+1+1/2=7/2

Is this correct?
 
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