Total Displacement Vectors Help

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The discussion revolves around calculating the net displacement of a boat that travels in multiple directions. Participants suggest drawing a diagram to visualize the boat's path, which aids in solving the problem. The calculations involve determining the components of the displacement vectors in both the x and y directions. After some back-and-forth on the equations, the final net displacement magnitude is calculated to be approximately 367.909. The conversation emphasizes the importance of breaking down the problem into manageable parts for clarity in solving vector displacement.
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Homework Statement



A boat travels West a distance of 200m, then North 400m, and finally 100m South of East at 30 degrees. What is the net displacement.

Homework Equations


none


The Attempt at a Solution


Many attempts none make sense...lol
 
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If you were to draw a diagram of the different parts of the boat's travels, don't you think that would make this problem easier to solve?
 
Yes i have drawn a graph and i just can't figure out how to find the displacement. like i don't know how to even go about finding it
 
SteamKing said:
If you were to draw a diagram of the different parts of the boat's travels, don't you think that would make this problem easier to solve?

Like this? %^)
 

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  • boat travel017.jpg
    boat travel017.jpg
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ok so Rx= -150 and Ry= 486.6...what do i have to do now to get the net displacement. Thanks for the graphic BTW
 
Now try to find Ry

\vec{R_y}=\vec{V_{1y}}+\vec{V_{2y}}+\vec{V_{3y}}

\vec{R_y}=0+400\hat{j}-100\sin{30}\;\hat{j}

if the figure drawn by spinnor is correct then , in his equations, there should be
\cos{30} in the equation for \vec{R_x}

so the net displacement would be

\vec{R}=\vec{R_x}+\vec{R_y}

where

\vec{R_x}=-200\hat{i}+100\cos{30}\;\hat{i}
 
ok so if I did my math right the answer should be 336.603. Is that correct?
 
I don't know if you are asked to get the answer as a magnitude or a vector. for magnitude I am getting 367.909
 

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