Vector question - North-east direction

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SUMMARY

The discussion focuses on resolving vector displacements for a particle undergoing three movements: S1 = √2 m North-East, S2 = 2 m South, and S3 = 4 m at 30 degrees North of West. Participants clarify the vector representation of these displacements, emphasizing the importance of sign conventions in vector components. The negative sign in the x-component of S3 is explained as a result of the second quadrant's coordinate system. Additionally, the discussion touches on vector products and their directional implications.

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  • #31
gracy said:
So why will their resultant be at 45 degrees?
Because
gracy said:
Direction of (A + B) is given to be northeast
 
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  • #32
gracy said:
Direction of (A + B) is given to be northeast
No, I meant in the solution direction of (A + B) is given to be northeast.
 
  • #33
Vector A is pointing eastwards and vector B northwards then direction of (A × B) × (A × B)
1)North - east
2)vertically upward
3)vertically downward
4)None of the above
I tried to draw it[/QUOTE]
I can't differentiate signs of usual multiplication and vector product here.
 
  • #34
gracy said:
No, I meant in the solution direction of (A + B) is given to be northeast.
Yes, I see your difficulty. Two ways out: interpret the question as asking which could be right; interpret the answer "north - east" as meaning in that general direction, i.e. in the NE quadrant. Neither very satisfactory I agree.
 
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  • #35
gracy said:
(A × B) × (A × B)
What is the angle between the two vector arguments to the central x?
 
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  • #36
haruspex said:
What is the angle between the two vector arguments to the central x?
Zero. Sin 0=0
 
  • #37
gracy said:
Zero. Sin 0=0
So what is (a x b) x (a x b)?
 
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  • #38
haruspex said:
So what is (a x b) x (a x b)?
zero
 
  • #39
gracy said:
zero
Right.
 
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