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Total Displacement Vectors Help

  1. Sep 5, 2011 #1
    1. The problem statement, all variables and given/known data

    A boat travels West a distance of 200m, then North 400m, and finally 100m South of East at 30 degrees. What is the net displacement.

    2. Relevant equations
    none


    3. The attempt at a solution
    Many attempts none make sense...lol
     
  2. jcsd
  3. Sep 5, 2011 #2

    SteamKing

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    If you were to draw a diagram of the different parts of the boat's travels, don't you think that would make this problem easier to solve?
     
  4. Sep 5, 2011 #3
    Yes i have drawn a graph and i just can't figure out how to find the displacement. like i dont know how to even go about finding it
     
  5. Sep 5, 2011 #4
    Like this? %^)
     

    Attached Files:

  6. Sep 5, 2011 #5
    ok so Rx= -150 and Ry= 486.6......what do i have to do now to get the net displacement. Thanks for the graphic BTW
     
  7. Sep 6, 2011 #6
    Now try to find Ry

    [tex]\vec{R_y}=\vec{V_{1y}}+\vec{V_{2y}}+\vec{V_{3y}}[/tex]

    [tex]\vec{R_y}=0+400\hat{j}-100\sin{30}\;\hat{j}[/tex]

    if the figure drawn by spinnor is correct then , in his equations, there should be
    [itex]\cos{30}[/itex] in the equation for [itex]\vec{R_x}[/itex]

    so the net displacement would be

    [tex]\vec{R}=\vec{R_x}+\vec{R_y}[/tex]

    where

    [tex]\vec{R_x}=-200\hat{i}+100\cos{30}\;\hat{i}[/tex]
     
  8. Sep 6, 2011 #7
    ok so if I did my math right the answer should be 336.603. Is that correct?
     
  9. Sep 7, 2011 #8
    I don't know if you are asked to get the answer as a magnitude or a vector. for magnitude I am getting 367.909
     
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