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Total distance in simple harmonic motion

  1. Apr 24, 2014 #1
    1. The problem statement, all variables and given/known data

    A mass oscillates along the x axis in simple harmonic motion. It goes through 200 cycles in 10 seconds and its vibrational amplitude is 0.020 m. What is the frequency, in hertz, and the total distance traveled, in meters, by the mass in the 200 cycles?


    2. Relevant equations



    3. The attempt at a solution

    I got the frequency but cannot understand how to get the total distance.
    The explanation just says "one cycle goes through distance 4A. 200 * 4A = 800A = 16m". Can someone explain this to me please?
     
  2. jcsd
  3. Apr 24, 2014 #2

    Pythagorean

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    Gold Member

    A is the Amplitude.
     
  4. Apr 24, 2014 #3
    Yes I know that, but I just don't understand how 800A equals 16.
     
  5. Apr 24, 2014 #4

    Pythagorean

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    Gold Member

    800*.02 = (8*100) * (2/100) = (100/100)*(8*2) = (1)*(16) = 16
     
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