1. The problem statement, all variables and given/known data Suppose a particle responds to this equation of motion: s = t2 - 5t + 6 a) find the velocity at two seconds and three seconds b) find the acceleration c) find the total distance covered after 3 seconds 2. Relevant equations s = t2 - 5t + 6 v = ds/dt = 2t - 5 a = dv/dt = 2 3. The attempt at a solution ai) 2t - 5 = 4 - 5 = -1 aii) 2t - 5 = 6 - 5 = 1 (everything is fine here) b) a = 2 c) The equation given above is for position, since it uses velocity. Is it actually possible to find the distance covered from the displacement? I also tried finding the position at t = 1, t = 2 and t = 3 to find the distance. at t = 1, s = 2 at t = 2, s = 4 - 10 + 6 = 0 at t = 3, s = 9 - 15 + 6 = 0 How is it possible that the displacement is 0 twice consecutively if the velocity is non-zero? Isn't that impossible? I was actually going to calculate the displacement each time then add all together. The book had also already given an answer: 6.5m, although i'm not sure of how they got that. Thanks for any answers.