Total Energy Of A Spring-Mass System

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SUMMARY

The total energy of a spring-mass system is correctly defined as Et = (k * A^2) / 2, where k is the spring constant and A is the amplitude. The maximum speed of a mass on a spring is given by the formula vmax = 2 * π * f * A, which aligns with the principles of simple harmonic motion. The discussion highlights a discrepancy in the workbook used for a Physics 12U course, which incorrectly states the total energy as Et = k * A^2. This error leads to confusion in deriving the maximum speed of the mass.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with the formulas for kinetic and potential energy
  • Knowledge of spring constants and amplitude in oscillatory systems
  • Basic algebra for rearranging equations
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  • Study the derivation of the total energy formula for spring-mass systems
  • Learn about the relationship between frequency (f) and angular frequency (ω) in harmonic motion
  • Explore the concept of energy conservation in oscillatory systems
  • Review common errors in physics textbooks and how to verify formulas
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Students in high school physics courses, educators reviewing curriculum materials, and anyone interested in understanding the dynamics of spring-mass systems in simple harmonic motion.

D3SI
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Hello everyone, I hope someone can help me with this simple harmonic motion question
I've been trying it for about an hour now and I think i may have found the problem but I want to run it by someone else :)
I'm taking this Phsyics 12U course (Uni prep for Ontario, Canada) through correspondence and all I have to go by are the work books that I have received.

Homework Statement



My work book gives me a bunch of formulas for harmonic motion, those formulas are what I am using to re-arrange and sub and so on.Prove that Max Speed of a mass on a spring is given by 2 * pi * f * A

So after re-arranging and all that fun stuff I get as far as

vmax= sqrt(k/m) * A===============================================

so now the speed of the mass will be at max when it is right at equilibrium (x = 0)
and the potential energy will be zero and the kinetic energy will be max

So then I get this formula using energy equations, (Ek = kinetic energy, m = mass)

vmax = sqrt(2 * Ek / m)

now we can get Ek another way, and that is using the total energy of the system equation and this is where i get hung up

in my workbook, it has the total energy of the system as

Et = kA^2

the total energy is all kinetic in this case so we can sub Ek for Et

so I try to plug that into

vmax = sqrt(2 * Ek / m)

and I end up with

sqrt(2k/m) * A


which kind of looks like the 2 * pi * f * A rearranged except for that useless 2 in the numerator! :@

so then I research this using google and on wikipedia it has the total energy of a spring mass system as

Et = (kA^2) / 2

so this formula has the same thing except the 2 in the denominator
I then check another site and it also has the 2 in the denominator

and it clicks, i put this formula in the equation instead and it all works out!

so is my workbook giving me bad information??

is the total energy of a Spring Mass system given as

Et = (k * A^2)

or

Et = (K * A^2) / 2

?

thanks in advance for all of the help!
 
Last edited:
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Hi D3SI,

Yes, you found the problem; there should be a (1/2) factor in the total energy formula.
 
woot!

thanks for the reply :)

gunna have a talk with the adult ed people at the high school, looks like they don't check the books b4 using em :(
 

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