Total Excess Charge using a Coulomb Balance

Click For Summary

Homework Help Overview

The discussion revolves around estimating the total excess charge on a conducting sphere charged to a potential of 2,000,000V in the context of a Coulomb Balance experiment. Participants are exploring the relevant equations and concepts related to this scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants inquire about specific equations to use for estimating charge, with references to potential and capacitance formulas. There are questions regarding the choice of a spherical shape for the experiment.

Discussion Status

Some participants have suggested potential equations, such as V = q/R and C = 4∏ε0r, while noting the importance of knowing the radius. The discussion is ongoing, with various interpretations and approaches being explored.

Contextual Notes

There is an emphasis on the need for specific values, such as the radius of the sphere, to apply the formulas correctly. The choice of geometry in the experiment is also under consideration.

ZedCar
Messages
353
Reaction score
1

Homework Statement



If conducting a Coulomb Balance experiment, and a question asks to estimate the total excess charge on a sphere with a conducting surface charged to 2,000,000V potential.

Is there a specific equation I should be using to estimate this?

Thank you.

P.S. why are spheres used in such an experiment, and not some other shape?
 
Last edited:
Physics news on Phys.org
ZedCar said:

Homework Statement



If conducting a Coulomb Balance experiment, and a question asks to estimate the total excess charge on a sphere with a conducting surface charged to 2,000,000V potential.

Is there a specific equation I should be using to estimate this?

Thank you.

P.S. why are spheres used in such an experiment, and not some other shape?

V = q/R
'cause they make the math easy.
 
Is it not C = 4∏ε0r

(Sorry for large font, I was trying to obtain a small 0 beside ε!)
 
ZedCar said:
Is it not C = 4∏ε0r

(Sorry for large font, I was trying to obtain a small 0 beside ε!)


Yes, sure. In either case though you have to know the value of r.

(I assume you got the right formula for C of a sphere.)
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
5K