Total Resistance of Parallel Wires: Copper & Aluminum

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SUMMARY

The discussion focuses on calculating the total resistance of two parallel wires: one copper wire with a diameter of 1.11 mm and one aluminum wire with a diameter of 2.23 mm, both measuring 1275 m in length. The total resistance is to be determined at three temperatures: 25°C, 105°C, and -40°C. The relevant equations include the formula for total resistance in parallel (1/Rt = 1/Ra + 1/Rc) and the resistance formula (R = resistivity * L / A). The resistivity values must be adjusted for temperature using the temperature coefficient for each material.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the concept of resistivity and its temperature dependence
  • Knowledge of the formula for calculating resistance in parallel circuits
  • Ability to perform calculations involving cross-sectional area based on wire diameter
NEXT STEPS
  • Research the temperature coefficients of resistivity for copper and aluminum
  • Learn how to calculate the cross-sectional area of a wire from its diameter
  • Explore the effects of temperature on electrical resistance in conductors
  • Study practical applications of parallel resistive circuits in electrical engineering
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and professionals involved in circuit design or materials science will benefit from this discussion.

talaroue
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Homework Statement



Two 1275m long wires are connected in parallel. One conductor is copper at 1.11mm in diameter and the other is aluminum at 2.23 mm in diameter. Find the total resistance of wires at 25 C, at 105 C, and minus 40 C.


Homework Equations



1/Rt=1/Ra+1/Rc
R=resistivity*L/A

The Attempt at a Solution



I thought I would just look up the resistivity and plug into the equation above...but then how do I incorporate temperature?
 
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The resistivity listed will be at some temperature, typically 25C (room temp.). There will also be a coefficient of temperature, where the resistivity increases with temperature. You will need to find that for each material, and incorporate it into your calculations.
 
O ok thank you. That was not in my notes!
 

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