A Trace of Numerator in QED vacuum polarization

Click For Summary
In QED vacuum polarization, the numerator includes momenta and gamma matrices, requiring a trace over Dirac-spinor space. This trace is necessary for loops with only fermion lines, such as in the photon self-energy calculation. In contrast, diagrams like fermion self-energy or vertex corrections do not involve traces due to the presence of photon propagators, resulting in matrices rather than complex-valued tensor components. The need for a Dirac trace stems from ensuring the output is consistent with the expected mathematical structure. Understanding these distinctions is crucial for accurate calculations in quantum electrodynamics.
Elmo
Messages
37
Reaction score
6
TL;DR
Basically this :
Why do we have to take the trace of the numerator when calculating the vacuum polarization loop ?
Sorry I just typed out my query .For some reason I can't seem to find the buttons for attaching files on this thread.

When writing the QED vacuum polarization loop, the numerator ,consisting momenta slashed + m from the fermion propagators and the two gamma matrices, has a trace over all of it.
Yet we do not take traces in other loop diagrams like fermion self energy or vertex correction.
Couldn't figure out why. Some clarification on it will be most helpful.
My best (and very vague) guess is that it has got something to do with the spinor completeness relation.
For reference see page 308 of Schwartz.
 
Physics news on Phys.org
actually here is that particular page.

Screenshot (123).png
 
You take traces (in Dirac-spinor space) if you have loops consisting of fermion lines only, as in this one-loop example where you calculate the 2nd-order contribution to the photon self-energy (or "vacuum polarization"). It's also clear that you need a Dirac trace, because the result must be usual complex-valued tensor components not some matrix in Dirac space. For the electron-self energy the analogous diagram has one fermion and one photon propgator in the loop, and there's thus no trace in Dirac space, and indeed the result must be a matrix in Dirac space.

Formally you get these Feynman rules (including the additional sign for a closed purely fermionic loop, also applicable in the calculation of the photon-self-energy diagram discussed here) of course from Wick's theorem.
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

Similar threads

  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
18
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K