Tracking a Falling Ball: Investigating Radius Over Time

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Homework Help Overview

The discussion revolves around a problem involving a ball of radius r that is falling from a height. The original poster is attempting to understand how the radius appears to change with respect to time as the ball falls, while neglecting air resistance.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster proposes that the radius decreases quadratically over time based on the equation of free fall. Some participants question the validity of this assumption, suggesting that it may refer to the visible angle from the observer's perspective rather than an actual change in the radius of the ball.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the relationship between the radius and the observer's perspective. Some guidance has been offered, indicating that the formula presented by the original poster may approximate the angle subtended at the observer's eye.

Contextual Notes

There is some uncertainty regarding the original problem statement and the terminology used, which may affect the clarity of the discussion. The original poster expresses a desire for better understanding and clarification of their thoughts.

Numeriprimi
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Homework Statement


We have got a ball of radius r, which is falling from the roof of the house. How is the radius r with respect to time? We are looking at the ball directly from above and ball is at the beginning of fall x from our eyes. Neglect air resistance.

Homework Equations


I'm not sure what to write here. So I think the nub is equation of free fall: s= 1/2gt^2 radius decreases quadratically

The Attempt at a Solution


So, I know equation: s= 1/2gt^2
I think the radius decreases quadratically, because t^2.
I must attributed the x (s from eyes before free fall)
And my equation: r(t)= r/(1/2gt^2 + x)

It is right? Thanks for help.

PS: Sorry for bad English, but I don't know better yet.
 
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If r is the radius of the ball, I don't see any reason why it should decrease. Do you mean the visible angle for the observer?
If the initial distance of the ball is large compared to the radius of the ball, your r(t) is an approximation for that angle.

Hmm... the original problem statement would be interesting - with translated words maybe ;).
 
No, no... How changing the radius of sight of the observer, when ball is falling free fall.

Hmmm... You don't interesting what I think? :-( Describe better?
 
Hi Numeriprimi! :smile:
Numeriprimi said:
So, I know equation: s= 1/2gt^2
I think the radius decreases quadratically, because t^2.
I must attributed the x (s from eyes before free fall)
And my equation: r(t)= r/(1/2gt^2 + x)
mfb said:
… Do you mean the visible angle for the observer?
If the initial distance of the ball is large compared to the radius of the ball, your r(t) is an approximation for that angle.

i agree with mfb :smile:

you seem to mean (half) the angle subtended at the eye, and your formula for r(t) confirms that (correctly, for small r) :wink:
 
So... Is my formula well?
 
your formula is good :smile:
 

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