Tracking a Falling Ball: Investigating Radius Over Time

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SUMMARY

The discussion focuses on the mathematical modeling of a falling ball's radius as perceived by an observer. The key equation utilized is the equation of free fall, s = 1/2gt², which leads to the conclusion that the perceived radius decreases quadratically over time. The participant's formula, r(t) = r/(1/2gt² + x), approximates the angle subtended at the observer's eye, confirming the relationship between distance and perceived radius. The consensus is that the formula is valid for small radii and large initial distances.

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  • Understanding of kinematics, specifically free fall equations
  • Basic knowledge of geometry, particularly angles and subtended angles
  • Familiarity with mathematical modeling concepts
  • Ability to interpret and manipulate algebraic expressions
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  • Study the implications of neglecting air resistance in free fall scenarios
  • Explore the concept of angular size and how it relates to distance
  • Investigate the effects of varying initial distances on perceived dimensions
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Students studying physics, particularly those interested in kinematics and mathematical modeling, as well as educators looking for examples of real-world applications of free fall equations.

Numeriprimi
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Homework Statement


We have got a ball of radius r, which is falling from the roof of the house. How is the radius r with respect to time? We are looking at the ball directly from above and ball is at the beginning of fall x from our eyes. Neglect air resistance.

Homework Equations


I'm not sure what to write here. So I think the nub is equation of free fall: s= 1/2gt^2 radius decreases quadratically

The Attempt at a Solution


So, I know equation: s= 1/2gt^2
I think the radius decreases quadratically, because t^2.
I must attributed the x (s from eyes before free fall)
And my equation: r(t)= r/(1/2gt^2 + x)

It is right? Thanks for help.

PS: Sorry for bad English, but I don't know better yet.
 
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If r is the radius of the ball, I don't see any reason why it should decrease. Do you mean the visible angle for the observer?
If the initial distance of the ball is large compared to the radius of the ball, your r(t) is an approximation for that angle.

Hmm... the original problem statement would be interesting - with translated words maybe ;).
 
No, no... How changing the radius of sight of the observer, when ball is falling free fall.

Hmmm... You don't interesting what I think? :-( Describe better?
 
Hi Numeriprimi! :smile:
Numeriprimi said:
So, I know equation: s= 1/2gt^2
I think the radius decreases quadratically, because t^2.
I must attributed the x (s from eyes before free fall)
And my equation: r(t)= r/(1/2gt^2 + x)
mfb said:
… Do you mean the visible angle for the observer?
If the initial distance of the ball is large compared to the radius of the ball, your r(t) is an approximation for that angle.

i agree with mfb :smile:

you seem to mean (half) the angle subtended at the eye, and your formula for r(t) confirms that (correctly, for small r) :wink:
 
So... Is my formula well?
 
your formula is good :smile:
 

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