Traffic Flow - Junction, Delay, Webster, Greatest Upper Bound

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SUMMARY

The discussion focuses on calculating the effective green time (g) in traffic flow analysis using the parameters q = 0.7 and a cycle length (c). The user determines that the greatest lower bound for g is 200/13, derived from the equations g ≥ 0.35c and c = g + 10. The user expresses uncertainty regarding whether the correct relationship is c = g + 10 or c = 2g + 10, indicating a need for clarification on these formulas.

PREREQUISITES
  • Understanding of traffic flow theory and parameters such as cycle length (c) and green time (g).
  • Familiarity with mathematical inequalities and algebraic manipulation.
  • Knowledge of traffic signal timing and its impact on junction performance.
  • Basic concepts of traffic demand represented by flow rates (q).
NEXT STEPS
  • Research traffic signal timing optimization techniques.
  • Learn about the relationship between green time and cycle length in traffic flow models.
  • Explore the implications of varying flow rates on traffic signal performance.
  • Study the mathematical foundations of traffic flow theory, focusing on inequalities and bounds.
USEFUL FOR

Traffic engineers, urban planners, and students studying transportation systems who are interested in optimizing traffic signal performance and understanding the mathematical relationships in traffic flow analysis.

MidnightR
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[PLAIN]http://img96.imageshack.us/img96/7816/12530747.jpg

Hopefully this will post successfully...

Erm its the first part I'm not sure on, after that it's easy. I'm just not understanding the wording.

I need to work out the effective green time during the cycle
 
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I believe since q = 0.7 then g > or = 0.35c what would this make the greatest lower bound? g = 0.35c?
 
Last edited:
Think I got it,

c=? q=0.7 s=2 therefore

g/c <=1
0.35c/g <= 1

therefore

g <= c <= g/0.35

we know c = g +10 so g= 10-c & sub in

c-10 <= c <= (c-10)/0.35

so assuming c is positive then

c >= 200/13 so take greatest lower bound = 200/13

however I'm still not sure that c = g+10 rather than c=2g+10
 
Last edited:

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