Jakecp
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I looked here https://en.m.wikipedia.org/wiki/Mechanical_advantage#Speed_ratio but it is just the MA
The discussion revolves around the mechanics of train wheels, focusing on the forces acting on them, the relationship between wheel size and traction, and the mechanical advantage in the context of locomotives. Participants explore concepts related to torque, angular and linear velocity, and the attachment of pistons to wheels.
Some participants have offered insights into the mechanics of the wheel and piston system, while others express confusion about the classification of levers and the roles of various points in the system. There is a productive exchange of ideas, with participants seeking clarification and further understanding.
Participants note the lack of specific measurements and definitions, which may impact their ability to fully analyze the problem. There is also mention of varying levels of familiarity with concepts such as angular and linear velocity, which may influence the discussion.
Consider two of the front gears on a bicycle, one twice the diameter of the other. Uphill, in low gear, I apply a steady torque to the pedals and turn them at some constant rate. That exerts a force F on the chain and and makes it move at speed v. Cresting the hill, I change to the high gear, but find applying the same torque keeps the pedals rotating at the same rate as before. The force on the chain drops to F/2, but the chain moves twice as fast. The power transferred is Fv in both cases.Jakecp said:You are right in that , but i don't get at 100% how does that happen? This : you can arrange to get twice the force if you accept getting half the speed, or you can get twice the speed if you accept only getting half the force.