A particle is located at r=(2i+4j)m at t=0s.
At t=3s it is at r=(8i-2j)m and has velocity v=(5i-5j)m/s
a)what is the particles acceleration vector a?
The Attempt at a Solution
this is where i have trouble:
I understand how my text uses this equation i just dont know were they got these numbers:
--> did they assume that r0=0? and how did they get r1?
and where did they get 2sv0 because from the information given i thought it was all 3seconds
okay well anyway i understand they would take the v0 found in the first part and sub it in to get this:
(3s^2)a+ (2s)[(5i+5j)m/s - 3s(a)] =(4i+4j)m
Please can someone explain to me where they got the 2 from
and also i dont understand how they subtract3s(a)
I would really appreciate it.