Transfer function from a Z = a - i * b number.

Click For Summary
The discussion centers on converting the output-to-input voltage relation of a circuit, expressed as Vout/Vin = 2 - 3i, into a transfer function suitable for MATLAB. Participants clarify that the expression represents a series resistor and capacitor, with the need to convert it into the s-domain for analysis. Key points include the impedance relationships for resistors, capacitors, and inductors, and the importance of understanding frequency in this context. The user expresses a desire for additional resources and acknowledges the complexity of the conversion process. Overall, the conversation emphasizes the need for clarity in transforming circuit parameters into a usable transfer function format.
Arif1996
Messages
3
Reaction score
0
I have a circuit where after a deduction of the impedance, I have found the output to input voltage relation as Vout/Vin = 2 - 3i

Can anyone please let me know how can I can convert it to s functions (such as G(s) = 1/1+s) in Matlab so that I can get a transfer function?

I would appreciate help, or a link to a document if that is preferred.
 
Engineering news on Phys.org
Thanks..but i swear to God..i have read those...i think i am missing a very small little connection...2 - 3i is supposed to be a resistor and capacitor in series..R and C...and now just have to convert that into s domain...i guess..i would need some more reading...once i have the numerater and denominator, i can just use the MATLAB function to find the transfer function...as i said...it's been a while since i have done this and just trying to peak some brain from a person who deals with this on a daily basis...

not trying to be slacker...i will resolve as time progress...
 
a capacitor is 1/sC and a resistor is R. An inductor is sL. So a series RC is R + 1/sC or you could say it is R + 1/jwC (I use j instead of i) which is R -j/wC

The impedance of a capacitor is 1/2πfc which is the same as saying 1/wC.
 
yes..you are absolutely correct..:-)...i am a bit suspicious about the frequency and the reason trying to see...if i am missing something while writing the TF...i will most likely take care of this on the coming week and your explanation really helped a lot...much appreciated...
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
5K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
9K
  • · Replies 2 ·
Replies
2
Views
1K