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Transfer function Of A Highpass Filter

  1. Jun 3, 2012 #1
    Please how do i transform this transfer function of a highpass filter

    H(w) = jwR2 / [ (R1R2/L) + jw(R1 + R2)] to

    H(w) = [R2/(R1+R2)][jw/(jw+wc)]

    wc is the corner freq.

    The circuit consists of a voltage source Vs(t) ,R1 in series with R2||L,Vo collected on R2.

    Thanks.
     
  2. jcsd
  3. Jun 3, 2012 #2

    I like Serena

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    Welcome to PF, jyde! :smile:


    We can draw R2 from the nominator.

    What do you get for the denominator if you extract (R1+R2)?
     
  4. Jun 3, 2012 #3
    The denominator will then be [{R1R2/L(R1+R2)} + jw](R1+R2)
     
  5. Jun 3, 2012 #4

    I like Serena

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    Good.

    So let's define wc=R1R2/L(R1+R2).

    Does [{R1R2/L(R1+R2)} + jw] look like (jw+wc)?
     
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