Transfer function to impulse response

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SUMMARY

The discussion focuses on computing the impulse response of a linear, time-invariant system given the transfer function H(z) = (z^2 + 5z) / (z^2 + 5). The primary challenge involves performing the inverse z-transform using partial fraction decomposition, particularly due to the irreducible quadratic term z^2 + 5. The solution involves recognizing that z^2 + 5 can be factored into (z - √5i)(z + √5i), allowing for the application of complex number techniques in z-transforms.

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  • Understanding of linear, time-invariant systems
  • Familiarity with z-transforms and their properties
  • Knowledge of partial fraction decomposition
  • Basic complex number operations
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Students and professionals in electrical engineering, control systems, and signal processing who are working on z-transform applications and impulse response calculations.

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Homework Statement


Given the transfer function of a linear, time-invariant system
[tex]H(z)=\frac{z^2+5z}{z^2+5}[/tex]
compute the impulse response.

Homework Equations


We are supposed to compute the inverse z-transform with partial fraction decomposition but the problem here is the irreducible quadratic function [tex]z^2+5[/tex].

The Attempt at a Solution


In our table of inverse z-transforms they are only functions of the the type
[tex]\frac{z^{m+1}}{(z-a)^{m+1}}[/tex]
I tried this.
[tex]H(z)=\frac{z^2+5z}{z^2+5}=\frac{z^2}{z^2+5}+5\frac{z}{z^2+5}[/tex]
I can compute the inverse z-transform of [tex]\frac{z^2}{z^2+5}[/tex] just fine, but how do I compute the inverse z-transform of [tex]\frac{z}{z^2+5}[/tex]

Thanks.
 
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It's not irreducible. [itex]z^2+5=(z-\sqrt{5}i)(z+\sqrt{5}i)[/itex]. Complex numbers are an important part of z transforms.
 
Last edited:
Ok thank you now I think I can solve it.
 

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