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Transfer of forces from a pulley to a beam

  1. Aug 3, 2016 #1
    1. The problem statement, all variables and given/known data
    I am trying to understand how forces transfer from a wheel / pulley onto a beam, and then calculating the resulting moment. The image describe the problem.

    trinser.png
    The rope is in tension with force "S", the wheel/pulley can rotate freely without any friction.

    2. Relevant equations

    M = force*distance


    3. The attempt at a solution
    Method 1: If we look at the global system it should be ok to use the force*distance to find the resulting moment M.

    Method 2: If we first calculate the forces acting between the pulley and the beam and then isolate the beam we should be able to find the moment.

    I thought method two would be right because the pulley don't transfer moment, but then again we should also be able to look at it as a global system. Which one is correct and why doesn't the other one work? Thanks :)
     
  2. jcsd
  3. Aug 3, 2016 #2

    BvU

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    Have you shown that the two methods are really different ?
    Do you let the two S act at the correct point in method 2 ?
     
  4. Aug 3, 2016 #3
    In theory the two methods shouldn't produce any differences. But if we look at the pulley as a isolated system and find the x and y forces acting in the bearing we are only left with M, but since the two S are producing the same moment with equal distance r my understanding is that M=0 in the bearing. Since the beam and pulley are connected in the frictionless bearing a can only see that the x and y component described in the picture are transferred to the beam.

    When you say
    Hmm, I can't see how I should set the forces differently
     
  5. Aug 3, 2016 #4

    BvU

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    Simple case ##\theta = \pi/2##. You let the horizontal S act at the height of the beam instead of (idem + r) and the vertical S at the end of the beam instead of (idem + r) -- but I do see the additional moments cancel, so perhaps that's what you mean ?
     
  6. Aug 3, 2016 #5
    Yes, if you use method 2 the moment cancels out in the pulley so you are left with a smaller M than what you get with method 1. Is it wrong to do a global analysis as in method 1 when you have freely rotating wheels in that system?

    Another way of stating the problem: Is the reaction moment force M at the end of the beam dependent on the radius of the pulley r?
     
  7. Aug 3, 2016 #6

    BvU

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    So my reasoning yields answer: no.

    Now we want to show that method 1 gives the same moment as method 2 ...
     
  8. Aug 4, 2016 #7
    Hmm, I have no idea why my earlier results yielded different numbers. Some times all you need is someone looking over your shoulder, thank you for your patience!
     
  9. Aug 4, 2016 #8

    haruspex

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    Different numbers or different-looking equations?
    Your two equations involve l, r, c and theta, but from the geometry there is a relationship between those variables, so it is not apparent whether they are actually the same. Figure out the relationship and substitute for c in method 1.
     
  10. Aug 4, 2016 #9
    Yes thanks. When I worked through it earlier I got different numbers. But working it out once more I found that the r cancels out when using method 1.
    So it all makes sense now :)
     
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