Transform PDE Problem Solutions with Fourier Transforms | Get Help Now

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The discussion focuses on solving a fourth-order partial differential equation (PDE) using Fourier transforms. The equation presented is d4u/dx4 + K2d2u/dt2 = 0, with boundary conditions u(0,t) = f(t), u'(0,t) = g(t), u''(L,t) = 0, and u'''(L,t) = 0. The initial conditions are clarified as u(x,0) = f(t) and u'(x,0) = g(t), which are essential for applying Fourier transforms effectively. The participant seeks guidance on how to proceed with the solution, emphasizing the need for understanding the role of initial conditions in the context of Fourier analysis.

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Homework Statement


Use Fourier transforms to get solution in terms of f(t) adn g(t)

Homework Equations


d4u + K2*d2u =0
dx4 (space) dt2

u(0,t)=f(t)
u'(0,t)=g(t)
u''(L,t)=0
u'''(L,t)=0

The Attempt at a Solution


I been working no it for hours the best I got is
k4U +K* (d2U/dt2) =0
I'm not sure where to go since i don't hve initial conditions

Really need someone to show me how to do the question or a similar one
 
Last edited:
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mike1111 said:

Homework Statement


Use Fourier transforms to get solution in terms of f(t) adn g(t)


Homework Equations


d4u + K2*d2u =0
dx4 (space) dt2

u(x,0)=f(t)
u'(x,0)=g(t)
u''(L,t)=0
u'''(L,t)=0

The Attempt at a Solution


I been working no it for hours the best I got is
k4U +K* (d2U/dt2) =0
I'm not sure where to go since i don't hve initial conditions
Yes, you do have initial conditions! They are u(x,0)= f(t) and u'(x,0)= g(t). (I assume the ' denotes differentiation with respect to t.)

Really need someone to show me how to do the question or a similar one
 
my fault, there aren't meant to be initial ocnidtion, just fixed the question
 

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