Transformation of Angles (Relativity)

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SUMMARY

The discussion focuses on the transformation of angles in the context of special relativity, specifically comparing the angle of a velocity vector of a particle and the angle of an inclined stick. The transformation equations provided are x' = xcosθ + ysinθ and y' = -xsinθ + ycosθ. The key insight is that an observer measures the direction of a line at a constant time in their own frame, which does not correspond to a constant time in another frame. This highlights the relativity of simultaneity in different reference frames.

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  • Understanding of special relativity concepts
  • Familiarity with coordinate transformations
  • Knowledge of trigonometric functions and their applications in physics
  • Basic grasp of velocity vectors in physics
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  • Explore the concept of simultaneity in different reference frames
  • Learn about the geometric interpretation of velocity vectors
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Students of physics, particularly those studying special relativity, as well as educators and anyone interested in understanding the implications of frame transformations on measurements of angles and velocities.

Phyrrus
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Homework Statement


Find and compare the transformations of the angle of the velocity vector of a particle and the angle of an inclined stick. The relationship between the two frames is as usual.

In frame S' a stick makes an angle of θ' with the x' axis. What is the angle θ measured in the S frame? What is the length in the S frame?

Homework Equations



x' = xcosθ + ysinθ
y' = -xsinθ + ycosθ ?

The Attempt at a Solution



I really have no idea what the question is really asking. Thanks.
 
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Hi Phyrrus! :smile:
Phyrrus said:
Find and compare the transformations of the angle of the velocity vector of a particle and the angle of an inclined stick.

When an observer measures the direction of a line (such as this stick), he does so at a constant time in his frame.

(you can think of a line as a point traveling at infinite speed in the observer's frame! :biggrin:)

A constant time in his frame is not a constant time in the new frame. :wink:
 
thanks mate
 

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