Transformations of y = -2√(3x-12)-5

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The equation of the image is y=-2sqrt(3x-12)-5
It said describe the series of transformations so i rewrote the eqn into the form af[k(x-p)]+q
I got -2sqrt(3(x-(-4))-5 is this correct?

Vertical stretch by a factor of 2 horizontal compression by a factor of 1/3, reflection in the x axis, horizontal translation 4 units left and vertical translation 5 units down?
 
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aisha said:
The equation of the image is y=-2sqrt(3x-12)-5
It said describe the series of transformations so i rewrote the eqn into the form af[k(x-p)]+q
I got -2sqrt(3(x-(-4))-5 is this correct?

Vertical stretch by a factor of 2 horizontal compression by a factor of 1/3, reflection in the x axis, horizontal translation 4 units left and vertical translation 5 units down?

Very close, ... 3(x-4)... translation of 4 units to the RIGHT... but everything looks fine.
 


Yes, the equation is correct. Your description of the series of transformations is also correct. The original equation can be rewritten in the form af[k(x-p)]+q as y=-2sqrt[3(x-4)]-5, which shows a vertical stretch by a factor of 2, horizontal compression by a factor of 1/3, reflection in the x-axis, horizontal translation 4 units left, and vertical translation 5 units down.