1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Transformations of y = ab^k(x-4) + c

  1. Feb 21, 2013 #1
    1. The problem statement, all variables and given/known data
    Describe the transformations that must be applied to the graph of y = 5^x to obtain the graph of y = 2 - 3(5^(x+4)) and complete the following table (attached)


    2. Relevant equations
    y = ab^k(x-4) + c


    3. The attempt at a solution
    I started filling out the table. First column was provided.
    Second column y = -3(5^x) I multiplied the y value by -3
    (-1,-3/6)
    (0,0)
    (1,-3)
    (2,-6)
    (3,-9)

    For the third column I'm not sure how to incorporate the 2-3. I know the graph shifts 4 units left, so I would subtract 4 from each x value. But that's all I understand.
    (-5, ?)
    (-4, ?)
    (-3, ?)
    (-2, ?)
    (-1, ?)

    I can answer the rest of the question once I figure out how to do this part.
    Thank you
     
  2. jcsd
  3. Feb 21, 2013 #2
    Forgot to attach image.
     

    Attached Files:

  4. Feb 21, 2013 #3

    Mark44

    Staff: Mentor

    Don't think of it as "2 - 3", since they represent different transformations.

    First look at y = 5x + 4, which represents a shift to the left by 4 units relative to the graph of y = 5x.

    Next, look at y = 3*5x + 4.
    Then look at y = -3*5x + 4.
    Finally, look at y = -3*5x + 4 + 2, which is the same as y = 2 - 3*5x + 4.
     
  5. Feb 22, 2013 #4
    Oh wow that easy. Great, thanks!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Transformations of y = ab^k(x-4) + c
Loading...