Transformer copper loss calculation

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tommoturbo
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Hello guys have a little problem



see if anyone can help

Homework Statement



Q the primary winding resistance is 125Ohms, Secondary is 0.7ohms calulate the transformers copper loss at full load.



now the transformers name plate is 240V 50Hz 28VA the earlier question explains it is a step down transformer delivering 12V



Homework Equations




so primary Current = Vp/Rp 240/125 = 1.92A



now I am not sure what figures to use to calc the current in secondary winding at full load





i get values from 40A 38.4A



and using formula Full load current = VA rating/primary voltage i get .116A



i need Is value for copper loss formula



Copper loss W= Ip(sq)xRp+Is(sq)+Rs
Copper loss W= 1.92(sq)x125+Is(sq)+0.7 don't know the equation for secondary current Is














any help appreciated
 
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First of all, you're not calculating the primary current correctly. Hint: what does 28 VA mean?

Once you have that, remember that power in = power out to work out the secondary full-load current.
 
thanks for the reply but I am lost now.

not entirely sure what to do with the 28VA but thought it was used somehow to calc secondary current

thought i did the priomary current ok though
I=V/R 240/125


am i on the wrong track?
 
"The VA rating is the math formula used in determining the amperage at a given voltage."

So my secondary voltage of 12 volts from a 28VA transformer will produce 2.33 amps...?

e.g., 28 VA ÷ 12 Volts = 2.33 Amps. am i correct.
 
does this apply to the primary current also


primary voltage of 240volts from a 28VA transformer will produce .116 amps...

e.g., 28 VA ÷ 240 Volts = .116 Amps.

thanks for you help in this
 
Brilliant thanks for the advice

:)
 
hey guys
i have a doubt
will turns ratio affect the amount of copper loss or core loss
i am a little bit confused in ds matr
 
tommoturbo said:
Hello guys have a little problem
see if anyone can help

Homework Statement


Q the primary winding resistance is 125Ohms, Secondary is 0.7ohms calulate the transformers copper loss at full load.
now the transformers name plate is 240V 50Hz 28VA the earlier question explains it is a step down transformer delivering 12V

Insufficient data.

Is 12 VRMS the unloaded secondary voltage?
Is this an imaginary transformer with the unloaded primary power dissipation equal to zero?
I don't know if this one counts, but are we to pretend that 'full load' is a purely resistive load?
 
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