Transformer Impedance and Ratio Calculations

  • Thread starter Thread starter photonxyz
  • Start date Start date
  • Tags Tags
    Transformer
Click For Summary
SUMMARY

The discussion centers on transformer impedance and ratio calculations, specifically with a transformation ratio (a) of 1/5, an input current (Ip) of 2 Amps, and a load impedance (ZL) of 2 ohms. The input impedance (Rin) is calculated using the formula Rin = A²ZL, resulting in 0.08 ohms. Additionally, the secondary current (IL) is derived from the relationship Is = a * Ip, yielding a value of 0.4 Amps. The calculations presented are confirmed as correct by participants in the discussion.

PREREQUISITES
  • Understanding of transformer theory and operation
  • Familiarity with electrical impedance calculations
  • Knowledge of Ohm's Law and current relationships in circuits
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study transformer turns ratio and its impact on voltage and current
  • Learn about calculating voltage across a load in transformer circuits
  • Explore advanced impedance matching techniques in electrical engineering
  • Investigate the effects of varying load impedances on transformer performance
USEFUL FOR

Electrical engineering students, educators, and professionals involved in circuit design and analysis, particularly those focusing on transformer applications and impedance calculations.

photonxyz
Messages
9
Reaction score
0

Homework Statement



See attached for a view of the problem

Variables a=transformation ratio= 1/5
Ip=2Amps
ZL=2 ohm resistor

Homework Equations


Q1 : Find the current magnitude of the current IL and the Voltage VL
Q2 : Find the input impedence.


The Attempt at a Solution



OK, my question is variable a, which is the transformation ratio is 1/5. From my reading the transformation ratio is equal to the number of turns of the primary divided by the number turns of the secondary...

How

so a= NP/NS = 1/5

NP =1 turn Per NS =5

Then, the input impedence should be Rin = A^2ZL

Rin = (1/5)^2(2 ohms)

Rin = .08 ohms

Does that look correct for the impedance?


Then for the current for IL, a = Is/Ip or Is = (a)(Ip) or Is = .4 amps


does it look correct?

Thanks for any response :)
 
Physics news on Phys.org
Yes, these figures look correct. You should be able to readily calculate VL now.
 
Awesome :) thanks for your response :)
 

Similar threads

Engineering Calculating Norton Equivalent Circuit for Complex Load Impedance
  • · Replies 2 ·
Replies
2
Views
2K
Engineering Source impedance using given voltage swing and power
  • · Replies 2 ·
Replies
2
Views
2K
Single-phase Transformer Calculations
  • · Replies 2 ·
Replies
2
Views
2K
How to wind a 5K audio tube amplifier transformer?
  • · Replies 9 ·
Replies
9
Views
3K
How to Simplify Backward Impedance Matching Equations?
  • · Replies 1 ·
Replies
1
Views
2K
Finding Turns Ratio and Average Current in the Primary Winding
  • · Replies 12 ·
Replies
12
Views
5K
Transformers and Active/Reactive power question from HW
  • · Replies 7 ·
Replies
7
Views
2K
Engineering How do short/open-circuit tests work for step-up transformers?
  • · Replies 7 ·
Replies
7
Views
3K
Determine source frequency and impedance
  • · Replies 4 ·
Replies
4
Views
6K
Transformer; make primary voltage x10 of the secondary voltage
  • · Replies 4 ·
Replies
4
Views
2K