Transformer Impedance and Ratio Calculations

[photonxyz]

Homework Statement

See attached for a view of the problem

Variables a=transformation ratio= 1/5
Ip=2Amps
ZL=2 ohm resistor

Homework Equations

Q1 : Find the current magnitude of the current IL and the Voltage VL
Q2 : Find the input impedence.

The Attempt at a Solution

OK, my question is variable a, which is the transformation ratio is 1/5. From my reading the transformation ratio is equal to the number of turns of the primary divided by the number turns of the secondary...

How

so a= NP/NS = 1/5

NP =1 turn Per NS =5

Then, the input impedence should be Rin = A^2ZL

Rin = (1/5)^2(2 ohms)

Rin = .08 ohms

Does that look correct for the impedance?


Then for the current for IL, a = Is/Ip or Is = (a)(Ip) or Is = .4 amps


does it look correct?

Thanks for any response :)

 

[negitron]

Yes, these figures look correct. You should be able to readily calculate VL now.

 

[photonxyz]

Awesome :) thanks for your response :)