Transformer; make primary voltage x10 of the secondary voltage

AI Thread Summary
Transformers operate on electromagnetic induction and Faraday's Law, where the secondary voltage is proportional to the number of turns on the secondary coil. To achieve a secondary voltage ten times greater than the primary voltage, a turns ratio of 1:10 is required, meaning the secondary coil must have ten times as many turns as the primary coil. This relationship is derived from the formula Vp/Vs = Np/Ns. The discussion emphasizes the importance of understanding these ratios for practical applications. The conversation concludes with a note of caution for anyone considering building a transformer.
AN630078
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Homework Statement
Hello, hypothetically if I wanted to create a transformer which had an output voltage is ten times the input voltage, how would I do this?
Relevant Equations
Vs=-Ns (dΦ)/(dt)
Vp/Vs=Np/Ns
I understand that transformers function using electromagnetic induction and Faraday's Law.
This implies; Vs=-Ns (dΦ)/(dt)
Meaning the secondary voltage is proportional to the number of turns on the secondary coil.
Vs∝Ns

Using the relationship; Vp/Vs=Np/Ns
If we want Vs=10Vp that would imply that we require a 10:1 turns ratio, i.e. ten times as many turns on the primary coil than the the secondary?
10Vp=10/1*Vs

So to increase the output voltage to ten times that of the input voltage would we just increase the number of turns on the secondary coil by 1/10 of that on the primary; so Ns=1?

Or if Vs and Ns are directly proportional then we would increase the number of by multiplying by 10?
 
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AN630078 said:
Using the relationship; Vp/Vs=Np/Ns
You directly get$$
V_s = N_s\; {V_p\over N_p} = V_p\; {N_s\over N_p} $$
So not 10 : 1 but 1 : 10
 
BvU said:
You directly get$$
V_s = N_s\; {V_p\over N_p} = V_p\; {N_s\over N_p} $$
So not 10 : 1 but 1 : 10
Thank you for your reply. Oh right, so if the turns ratio is 1:10 not 10:1 would that imply that in order to produce an output voltage ten times the input voltage one would have 10 times turns on the secondary coil than the primary coil?
 
AN630078 said:
Thank you for your reply. Oh right, so if the turns ratio is 1:10 not 10:1 would that imply that in order to produce an output voltage ten times the input voltage one would have 10 times turns on the secondary coil than the primary coil?

That's right. Are you thinking of building one? Caution!
 
Gordianus said:
That's right. Are you thinking of building one? Caution!
Thank you for your reply. Haha, no presently it is a hypothetical curiosity. Although, perhaps it is an aspiration I will indulge when I feel I have a better theoretical understanding of their functioning. 👍Indeed I will heed your message of caution at any rate.
 
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