Transformer with attached load: required source voltage

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Homework Help Overview

The discussion revolves around a problem involving a power transformer with a turns ratio of 1:5, where the primary voltage is 400V and the secondary current is 100A. Participants are tasked with calculating the required source resistance for maximum power transfer in the circuit.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between primary and secondary voltages and currents, and the implications for source resistance. Questions arise regarding the concept of maximum power transfer and the equality of primary and secondary resistances.

Discussion Status

There is an ongoing exploration of the calculations related to the transformer, with some participants questioning the accuracy of the original calculations. Guidance has been offered regarding the definitions of source and load resistances, and the role of impedance in transformers.

Contextual Notes

Participants are navigating potential misunderstandings in the calculations and definitions related to transformer operation and maximum power transfer principles. There is acknowledgment of mistakes in previous calculations, which may affect the discussion's direction.

Kev1n
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1. A large power transformer has a turns ratio N1 / N2 of 1:5. When the primary voltage is 400v and it is connected to a resistive load its secondary current is 100A. Calculate the required value of source resistance of the supply to give a maximum power trnasfer



2. Vp = 400v, Ratio 1:5, Is = 100A



3. Vp = 400v, 1:5 Vs = 2000, Is = 100A, 1:5, Ip = 20A
R = Vp/Ip = 4 ohms.
I am a bit lost here, any pointers
 
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Kev1n said:
2. Vp = 400v, Ratio 1:5, Is = 100A

3. Vp = 400v, 1:5 Vs = 2000, Is = 100A, 1:5, Ip = 20A
R = Vp/Ip = 4 ohms.
I am a bit lost here, any pointers

So far so good. :cool:

What can you say about "maximum power transfer" of a simple circuit?
 


collinsmark said:
So far so good. :cool:

What can you say about "maximum power transfer" of a simple circuit?

The Rp and Rs should be equal?
 


Is that what you meant
 


Kev1n said:
The Rp and Rs should be equal?
[...]
Is that what you meant

I guess it depends on what you mean by 'Rp' and 'Rs'. But if you define Rp as the resistance in the primary and Rs as the resistance in the secondary, then 'No'. (Transformers not only modify voltage and current, but also impedance.)

Try again by putting things in terms of Rsource and RL, where

Rsource is the source resistance of the supply (which is what you are solving for in this problem), and
RL is the load resistance, as seen by the primary source.
 


Kev1n said:
1. A large power transformer has a turns ratio N1 / N2 of 1:5. When the primary voltage is 400v and it is connected to a resistive load its secondary current is 100A. Calculate the required value of source resistance of the supply to give a maximum power trnasfer

2. Vp = 400v, Ratio 1:5, Is = 100A

3. Vp = 400v, 1:5 Vs = 2000, Is = 100A, 1:5, Ip = 20A
R = Vp/Ip = 4 ohms.
I am a bit lost here, any pointers

collinsmark said:
So far so good. :cool:



Hello Kev1n,

Forgive me for speaking too soon in my first response. I may have caused some confusion. I seem to have skimmed over your attempted solution, and I missed a mistake.

Your calculation for Ip is incorrect in your original post. And your calculation of R = Vp/Ip = 4 ohms is also incorrect. Forgive me for the confusion of stating "so far so good." :blushing:

But what I said before about transformers changing impedance is true.
 

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