Transforming Matrix Addition to Multiplication without Exponentiation

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    Matrix Transformation
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Discussion Overview

The discussion revolves around the transformation of matrix addition into matrix multiplication, specifically exploring whether it is possible to express the sum of two matrices A and B as a product A.B without resorting to exponentiation. Participants examine the implications of matrix exponentiation and the conditions under which certain identities hold.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant inquires about transforming matrix addition A + B into multiplication A.B without using exponentiation, expressing concern about the nature of the results from exponentiation.
  • Another participant confirms the identity e^{A+B} = e^A e^B, questioning the meaning of "exponentiation gives an infinite answer."
  • It is noted that the identity e^{A+B} = e^A e^B holds if and only if matrices A and B commute (AB = BA).
  • There is a clarification that A and B must be n x n matrices for the discussed properties to apply.
  • One participant explains that the multiplication A.B results in a finite matrix, while the product e^A e^B does not yield an infinite result, challenging the initial claim.
  • A subsequent query is raised about the existence of a matrix X such that A.B = X(e^A e^B).
  • Another participant proposes a potential solution for X as X = ABe^{-(A+B)}.
  • One participant suggests that the inquiry might relate to a logarithm function, noting that such a function would be restrictive and not generally distributive.

Areas of Agreement / Disagreement

Participants express differing views on the nature of matrix exponentiation and its implications, particularly regarding the finiteness of results. The discussion includes both agreement on certain mathematical identities and disagreement on the interpretation of those identities and their applications.

Contextual Notes

Participants highlight the need for matrices A and B to be of the same dimensions (n x n) for the discussed properties to hold, and there is an acknowledgment of the complexities involved in transforming addition into multiplication.

aliya
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Suppose two matrices A and B . i want to transform matrix addition to matrix multiplication. e.g A+B into A.B.
Can anybody please tell me of any way i can do it ,except exponentiation? exponentiation gives an infinite answer.
 
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aliya said:
Suppose two matrices A and B . i want to transform matrix addition to matrix multiplication. e.g A+B into A.B.
Can anybody please tell me of any way i can do it ,except exponentiation? exponentiation gives an infinite answer.

It is certainly true that [itex]e^{A+ B}= e^Ae^B[/itex] but what do you mean by "exponentiation gives an infinite answer"?
 
HallsofIvy said:
It is certainly true that [itex]e^{A+ B}= e^Ae^B[/itex] but what do you mean by "exponentiation gives an infinite answer"?

[itex]e^{A+ B}= e^Ae^B[/itex] if and only if [itex]AB = BA[/itex]
 
trambolin said:
[itex]e^{A+ B}= e^Ae^B[/itex] if and only if [itex]AB = BA[/itex]

Don't A and B also need to be n x n matices?
 
Last edited:
Thankyou all for your replies.
"By exponentiation gives an infinite answer" i meant that suppose two matrices A and B, their multiplication A.B gives a finite answer i.e another finite matrix. but e^A.e^B give an infinite answer. doesn't it? Also can you please tell if there exists any X such that A.B=X(e^A.e^B)?
 
aliya said:
Thankyou all for your replies.
"By exponentiation gives an infinite answer" i meant that suppose two matrices A and B, their multiplication A.B gives a finite answer i.e another finite matrix. but e^A.e^B give an infinite answer. doesn't it?
No, it doesn't. If A and B are n by n matrices, then so are [itex]e^A[/itex], [itex]e^B[/itex], and [itex]e^Ae^B[/itex].

Also can you please tell if there exists any X such that A.B=X(e^A.e^B)?
 
ok thanks but " can you please tell if there exists any X such that A.B=X(e^A.e^B)?"
 
?? Of course their is:
[tex]X= ABe^{-(A+ B)}[/tex]
 
I think he is trying to come up with a logarithm function. But that would be quite restrictive since the function wouldn't be distributive in general.
 

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