Transistors: Collector vs Emitter (where does the symmetry get broken)

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SUMMARY

The discussion clarifies the distinctions between the collector and emitter in bipolar junction transistors (BJTs), emphasizing that the collector is lightly doped while the emitter is heavily doped. This doping difference is crucial for the collector-base junction to withstand higher reverse voltages, typically around 30 to 40 volts for low power BJTs. The asymmetry in doping levels enhances injection efficiency, allowing for greater current gain by minimizing wasted base current. The physical structure of BJTs is inherently non-symmetrical, which is essential for their proper functioning.

PREREQUISITES
  • Understanding of bipolar junction transistors (BJTs)
  • Knowledge of semiconductor doping levels
  • Familiarity with transistor operation principles (active and reverse bias)
  • Basic grasp of electronic circuit design
NEXT STEPS
  • Study the impact of doping levels on BJT performance
  • Learn about the reverse breakdown voltage in BJTs
  • Explore the concept of injection efficiency in transistors
  • Examine the physical structure of BJTs through cross-sectional diagrams
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Electronics students, circuit designers, and engineers interested in understanding the operational principles of bipolar junction transistors and optimizing their performance in electronic circuits.

aeftimia
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I thought I had a good understanding of transistors, but I have seen articles on how to tell the collector from the emitter. I had always pictured transistors as a perfectly symmetrical device. Either side could be the collector, and the opposite side was the emitter. Clearly, there is some subtlety I am missing.

So what physically makes the collector and emitter distinct?
 
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iThey is no way it is symetrical. Collector is very lightly doped and emitter is heavily doped. That's the reason collector base junction can take a larger reverse voltage. You can make the device work like a transistor if you reverse the C and E, but it don't not work very well.
 
If it was perfectly symmetrical, both active and reverse bias regions would be identical.

Collector is very lightly doped because, after reverse biasing the base-collector, you can "collect" charge carries over that very large depletion region.

Remember: lighter doping, wider depletion region.
 
Bassalisk said:
If it was perfectly symmetrical, both active and reverse bias regions would be identical.

Collector is very lightly doped because, after reverse biasing the base-collector, you can "collect" charge carries over that very large depletion region.

Remember: lighter doping, wider depletion region.

The lighter doping (and hence wider depletion region on the collector side of the CB junction) is, as yungman said, to increase the reverse breakdown voltage of the CB junction.

Even low power general purpose BJT's are usually designed for a CB reverse bias voltage of around 30 too 40 volts, with higher voltage devices requiring several hundred volts or more. Remember that under normal forward bias (active region) operation the CB junction is in fact reverse biased. If the same doping was used on the collector as was used on the emitter, most transistors would be unable to operate at much more than about 4 to 5 volts (Vce).

For the emitter, the higher levels of doping are used to increase the injection efficiency. For example, in an npn transistor, the heavy n+ doping in the emitter causes the vast majority of current across the BE junction to be electrons emitted from the n side (the emitter) rather than holes emitted from the base. Any holes emitted from the base are just "wasted" current, contributing to base current but contributing nothing collector current, and hence greatly reducing current gain.
 
Last edited:
It's helpful to look at the cross section of an actual BJT like in the image below:
http://www.allaboutcircuits.com/vol_3/chpt_2/8.html#03302.png

As you can see there are asymmetries in both the geometry and the doping.
 

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