Translational Equilibrium Practice problem

Thread starter hraghav
Start date Feb 18, 2024
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Equilibrium Translational

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The discussion centers on resolving a translational equilibrium practice problem. A participant identified a mistake in their calculations related to the force of the rope vector. They clarified that the correct frictional forces should be 180 degrees in the x-axis and 90 degrees in the z-axis. Additionally, the correct normal force values are 90 in the x-axis and 0 in the z-axis. The conversation emphasizes the importance of accurate vector considerations in solving equilibrium problems.

Feb 18, 2024

hraghav

Homework Statement: So I am basically stuck at one of the practice problems. The questions states that: A box of mass 𝑀=52.9kg is on a rough surface. It is being pulled by a force of magnitude 𝑇 at an angle of 𝜃=18.4 degrees with the horizontal. The box has a coefficient of static friction 𝜇=0.393 with the surface. What is the angle the force of friction makes with the positive x-axis and positive z-axis? What is the angle the normal force makes with the positive x-axis and positive z-axis?

Relevant Equations: So for frictional force angles I tried to do 180 - 18.4 = 161.6 degrees for x axis as frictional force is in the opposite direction of the force applied and z axis is 18.4. For normal force x axis I did 18.4 and z axis I did 90-18.4. But I got all of them wrong not sure what I am doing wrong. Could someone please help me with this. I have also attached a picture for the problem for reference. Thank you!

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Feb 18, 2024

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Feb 19, 2024

hraghav

Thank you I did find my mistake, I was considering the force of rope vector for my calculations. which was not the right way. The correct answer for the frictional forces was 180 degree in x axis and 90 in the z axis and for normal force was 90 x axis and 0 in the z axis!

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