Translational Equilibrium Practice problem

Thread starter hraghav
Start date Feb 18, 2024
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Equilibrium Translational

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SUMMARY

The discussion centers on a translational equilibrium practice problem where the user identified a mistake in their calculations regarding the force of the rope vector. The correct values for the frictional forces were determined to be 180 degrees in the x-axis and 90 degrees in the z-axis. Additionally, the normal force was established as 90 degrees in the x-axis and 0 degrees in the z-axis, providing clarity on the correct approach to solving the problem.

PREREQUISITES

Understanding of translational equilibrium concepts
Familiarity with vector forces in physics
Knowledge of coordinate systems (x-axis and z-axis)
Basic skills in solving physics problems involving forces

NEXT STEPS

Review vector force calculations in translational equilibrium
Study the principles of frictional forces and their angles
Learn about normal forces in different coordinate systems
Practice additional problems involving equilibrium and forces

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Students studying physics, educators teaching mechanics, and anyone looking to improve their problem-solving skills in translational equilibrium scenarios.

Feb 18, 2024

hraghav

Homework Statement: So I am basically stuck at one of the practice problems. The questions states that: A box of mass 𝑀=52.9kg is on a rough surface. It is being pulled by a force of magnitude 𝑇 at an angle of 𝜃=18.4 degrees with the horizontal. The box has a coefficient of static friction 𝜇=0.393 with the surface. What is the angle the force of friction makes with the positive x-axis and positive z-axis? What is the angle the normal force makes with the positive x-axis and positive z-axis?

Relevant Equations: So for frictional force angles I tried to do 180 - 18.4 = 161.6 degrees for x axis as frictional force is in the opposite direction of the force applied and z axis is 18.4. For normal force x axis I did 18.4 and z axis I did 90-18.4. But I got all of them wrong not sure what I am doing wrong. Could someone please help me with this. I have also attached a picture for the problem for reference. Thank you!

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Feb 18, 2024

Orodruin

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Please show us what you actually did.

Feb 19, 2024

hraghav

Thank you I did find my mistake, I was considering the force of rope vector for my calculations. which was not the right way. The correct answer for the frictional forces was 180 degree in x axis and 90 in the z axis and for normal force was 90 x axis and 0 in the z axis!