Transverse Wave on a Hanging Cord

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Homework Help Overview

The problem involves a uniform cord of length L and mass m, suspended vertically, and focuses on the speed of transverse waves and the time taken for a pulse to travel along the cord. The subject area is wave mechanics, specifically the behavior of waves in a medium with varying tension.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between tension and height in the cord, questioning how the variable height h affects wave speed. There is an exploration of the formula for wave speed and the implications of varying tension along the cord.

Discussion Status

The discussion is progressing with participants clarifying the concept of variable tension along the cord. Some have recognized that h is not a constant but a variable that influences the tension and, consequently, the wave speed.

Contextual Notes

Participants are navigating the implications of the problem's setup, particularly the relationship between tension, height, and wave speed. There is an acknowledgment of the need to consider how tension changes along the length of the cord.

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[SOLVED] Transverse Wave on a Hanging Cord

Problem. A uniform cord of length L and mass m is hung vertically from a support. (a) Show that the speed of tranverse waves in this cord is [itex]\sqrt{gh}[/itex] where h is the height above the lower end. (b) How long does it take for a pulse to travel upward from one end to the other?

For (a), I know that the speed of a transverse wave on a cord is given by [itex]v = \sqrt{T/\mu}[/itex] where T is the tension on the cord and [itex]\mu[/itex] is the linear density. As far as I understand, T = mg and [itex]\mu = m/L[/itex] so [itex]v = \sqrt{gL}[/itex]. Now, unless h = L (which I know isn't), I don't see how h plays a role here.

The answer to (b) is just L/v obviously.
 
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Realize that the tension varies along the length of the cord.
 
Let's measure the cord from the bottom up with the bottom being y = 0 until y = L. Then tension on the cord at y is [itex]\mu y g[/itex]. Is that what you mean when you wrote that the tension varies along the cord?
 
Absolutely. Using the terminology of the problem statement, [itex]T = \mu g h[/itex].
 
Ah, OK. I get it now. I thought h was some constant like L, not a variable.
 

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