Trasverse wave wavelenght and velocity problem

Click For Summary
SUMMARY

The discussion focuses on calculating the wavelength and velocity of transverse waves traveling along a tense rope with an amplitude of 10 cm. The distance between two consecutive waves is given as 6 cm, while the maximum transverse speed is 0.1 m/s. The correct approach involves using the wave equation y = A sin(ωt) and deriving it to find the maximum transverse speed, which leads to determining the frequency and subsequently the wave speed using the formula v = fλ.

PREREQUISITES
  • Understanding of wave mechanics, specifically transverse waves.
  • Familiarity with wave equations, particularly y = A sin(ωt).
  • Knowledge of angular wave number k and its relationship to wavelength λ.
  • Basic calculus for deriving equations with respect to time.
NEXT STEPS
  • Study the derivation of the wave equation y = A sin(ωt) and its implications for wave motion.
  • Learn how to calculate frequency from maximum transverse speed using the formula Aw = 2πfA.
  • Explore the relationship between wave speed, frequency, and wavelength in more depth.
  • Investigate the effects of tension and mass density on wave speed in ropes and strings.
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators and tutors seeking to clarify concepts related to transverse waves and their properties.

mmoadi
Messages
149
Reaction score
0

Homework Statement



Along a long tense rope are traveling transverse waves with amplitude A= 10 cm. What is the wavelength, if at any given time the distance between two consecutive neighboring waves y= 5 cm is d= 6 cm? With what velocity are the waves spreading, if the maximum transverse speed of the rope is ω= 0.1m/s?

Homework Equations



v= fλ
k= 2π/ λ
y= A sin(k*x)

The Attempt at a Solution



For the wavelength:
k= 2π/ λ → λ= 2π/ k

Calculating k:
y= A(sin k)(sin x) → sin k= y/ A(sin x)
sin k= 5, which is wrong

Where is my mistake?
 
Physics news on Phys.org
I don't understand what you did, but the equation for a wave is y=Asin(wt). (Note that the w here is different from the w in the question.) Derive that with respect to t and you get dy/dt=Awcos(wt), so Aw is the rope's maximum transverse speed. From there you can get the frequency, which you can then multiply by the wavelength to get speed.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 5 ·
Replies
5
Views
10K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K