Amplitude at the point of interference

[JohnLCC517]

Homework Statement

[/B]
Consider 2 radio antennas placed on a 2 dimensional grid at points x₁ = (300,0) and x₂ = (-300, 0). If the antennas are out of phase such that ϕ2-ϕ1 = π/4 and both are emitting waves of frequency 2.59 MHz. What will the amplitude of the resultant wave be at the point (200, 800)? Radio waves being a form of light travel at a speed of 3x108 m/s. You may assume at the point of interference that the two waves have the same amplitude and you may leave your final answer in terms of this amplitude.

Homework Equations

c = √(a²+b²) , Δφ = 2π(Δx/λ) , D(x,t) = A sin(kx – ωt + ϕ₀).

The Attempt at a Solution

I began this problem by getting the distance from x₁ and x₂ to the point (200, 800). The results I got were as follows;
From x₁ = 943.4
From x₂ = 806.2
I would use these values as my displacement values.

Following that I used the formula Δφ = 2π(Δx/λ) to determine the wavelength;
Δφ = 2π(Δx/λ) → λ = 2π(Δx/Δφ)
From x₁
λ = 2π(500/(π/4)) = 4000
From x₂
λ = 2π(100/(π/4)) = 800

This allowed me to get the wave number via k = 2π/λ.
x₁ wave number k = 2π/4000 = 0.0016
x₂ wave number k = 2π/800 = 0.0079

To get the angular frequency ω I used the formula ω = 2π⋅f.
x₁ ω = 2π⋅f = 2π(2.59) = 16.27
x₁ ω = 2π⋅f = 2π(2.59) = 16.27

My phase constants used were;
φ₁ = 0
φ₂ = π/4

And this is as far as I was able to get. I still need to find the Amplitude of the resultant wave but am left with the time variable t still unsolved. My initial thought would be to take A sin(kx – ωt + ϕ₀) of each wave, set the two sides equal to each other, drop the Amplitude because they will be the same and will therefore cancel, and solve for time in this formula but I am not sure if this is an appropriate way to approach this. Perhaps the time value t doesn't matter because the waves will intersect that point at the same time and have the same angular frequency so the values will be identical. I suppose what I'm looking for is a nudge in the right direction to ensure that I'm thinking about this in the right way.

 

[haruspex]

Following that I used the formula Δφ = 2π(Δx/λ) to determine the wavelength;

in that formula, what, exactly, do the phase difference and $\Delta x$ represent? Does that fit with the given phase difference and path difference you calculated?
What other information is available to you to find wavelength?