Traveling quantum Gaussian wave packet

In summary, the conversation discusses solving the Schrodinger equation for a free particle and deriving the probability density function at t>0. The initial state is described by the wavefunction Psi(x,0) = sqrt(pi_0(x))exp(iQx), where Q is a constant and pi_0 is a normalized Gaussian distribution function. The solution involves finding the functional form of sigma(t) and the relation between v and Q. The hint suggests using the parameters tau and l to simplify the equations. The conversation also touches on the general method for solving the SDE for any potential and the interpretation of the solution.
  • #1
boudreaux
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0
Homework Statement
Solve the Schrodinger equation and show the probability density is as follows
Relevant Equations
The Schrodinger equation for a free particle is

$$ih(\partial \Psi/\partial t) = -\frac{\hbar}{2m} \partial^2 \Psi/ \partial x^2$$

Consider an initial state described by the wavefuntion

$$\Psi(x,0) = \sqrt {(\pi_0(x))}exp(iQx)$$

where Q is a constant and $$\pi_0$$ is a normalized gaussian distribution function with zero mean and variance $$(\sigma_0)^2$$

$$\pi_0(x) = (1/\sqrt{(2\pi)\sigma_0})*exp(\frac{-x^2}{ 2(\sigma_0)^2})$$

Solve the schrodinger equation and show that the probability density $$\pi(x,t) = |\Psi(x,t)|^2 $$ at t>0 is given by

$$\pi(x,t) = (1/\sqrt{(2\pi)\sigma(t))}exp( (-\frac{(x-vt)^2) }{ (2\sigma(t)^2) })$$

What are the formulas $$\sigma(t)$$ and v?

Hint: might be easier to use $$\tau = 2m(\sigma_0)^2/\hbar , l = 2Q(\sigma_0)^2 $$
I tried plugging Psi into the right of the Schrodinger equation but can't get anything close to the solution or anything that is usable. How should I solve this?
 
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  • #3
updated with LaTeX!
 
  • #4
First, be careful that you are not trying to put ##\Psi(x,0) ## into the Schrodinger equation. That is the ##t=0## boundary condition. You need ##\Psi(x,t)##.

Recall that ##| \Psi |^2 ## means multiply ##\Psi## by its complex conjugate. So that means that the ##\exp (i Q x) ## factor does not appear in ##\pi (x,t)##. It's just a phase, so when you do the abs-square you get 1.

So maybe ##\Psi(x,t) ## can be obtained by the obvious means of putting the ##t## back into the ##\Psi(x,0)## formula?

$$ \Psi(x,t) = \sqrt{\pi(x,t)} \exp(i Q x)$$

This does give you back the correct ##\Psi(x,0) ##. So now, if you put this in the S.E., and turn the crank, you should get something that involves an equation in ##\sigma(t)##. And the ##(t)## part is trying to suggest that it is only a function of time. Meaning the ##x## parts of the S.E. should be identically solved by the form of ##\Psi(x,t)##. Check that is true. If it's not, can you guess what has to be added to ##\Psi(x,t)## to make it true? Remember that ##\pi(x,t)## can't change, so the additional stuff has to be just a phase.

When you struggle through that, you should be able to pull out a functional form for ##\sigma(t)## and a relation between ##v## and ##Q##.

The hint is telling you that the equation might be simpler if you change the time coordinate to the indicated parameter. It may mean that a bunch of the constants in front of the ##\Psi## are cancelled, meaning your equations are a lot easier to write.
 
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  • #5
boudreaux said:
Homework Statement:: Solve the Schrodinger equation and show the probability density is as follows
Relevant Equations:: The Schrodinger equation for a free particle is

$$ih(\partial \Psi/\partial t) = -\frac{\hbar}{2m} \partial^2 \Psi/ \partial x^2$$

Consider an initial state described by the wavefuntion

$$\Psi(x,0) = \sqrt {(\pi_0(x))}exp(iQx)$$

where Q is a constant and $$\pi_0$$ is a normalized gaussian distribution function with zero mean and variance $$(\sigma_0)^2$$

$$\pi_0(x) = (1/\sqrt{(2\pi)\sigma_0})*exp(\frac{-x^2}{ 2(\sigma_0)^2})$$

Solve the schrodinger equation and show that the probability density $$\pi(x,t) = |\Psi(x,t)|^2 $$ at t>0 is given by

$$\pi(x,t) = (1/\sqrt{(2\pi)\sigma(t))}exp( (-\frac{(x-vt)^2) }{ (2\sigma(t)^2) })$$

What are the formulas $$\sigma(t)$$ and v?

Hint: might be easier to use $$\tau = 2m(\sigma_0)^2/\hbar , l = 2Q(\sigma_0)^2 $$

I tried plugging Psi into the right of the Schrodinger equation but can't get anything close to the solution or anything that is usable. How should I solve this?

How do you solve the Schroedinger equation (SDE) for any potential? What's the general method?

##v## must be related to ##Q## in some way, which you may have to work out as part of the solution. Similarly, ##\sigma(t)## represents the standard deviation of the Gaussian at time ##t##. Note that the solution remains a Gaussian, but its standard deviation changes with time, and this is something else that should come out of your solution.

Note that ##\exp{iQx}## is not a phase factor, as it includes the variable ##x##. Do you know or can you guess what this factor represents? Hint: what does ##v## often represent.

Can you intepret the solution? Before you solve it, it might be useful to see whether you can figure out what the solution means.

This problem, I would say, is less than easy! If you are unsure of what you are doing with the SDE, I suggest you find some less complicated examples before returning to this.

If you do press ahead, get your algebra hat on.
 
  • #6
boudreaux said:
$$\pi_0(x) = (1/\sqrt{(2\pi)\sigma_0})*exp(\frac{-x^2}{ 2(\sigma_0)^2})$$

I'd check that expression. I think it should be:$$\pi_0(x) = \frac{1}{\sigma_0\sqrt{2\pi}}\exp(\frac{-x^2}{ 2(\sigma_0)^2})$$
 
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1. What is a traveling quantum Gaussian wave packet?

A traveling quantum Gaussian wave packet is a mathematical representation of a quantum particle that can move through space while maintaining a Gaussian distribution of its wave function. It is often used to describe the behavior of quantum systems, such as electrons, atoms, or photons, in motion.

2. How is a traveling quantum Gaussian wave packet different from a regular Gaussian wave function?

A traveling quantum Gaussian wave packet differs from a regular Gaussian wave function in that it includes a phase factor that accounts for the particle's momentum and position in space. This allows the wave packet to evolve and spread out as it travels, unlike a regular Gaussian wave function which remains stationary.

3. What are the applications of traveling quantum Gaussian wave packets?

Traveling quantum Gaussian wave packets have a wide range of applications in fields such as quantum mechanics, optics, and quantum computing. They are used to model the behavior of particles in motion, study quantum interference and tunneling phenomena, and design quantum communication and information processing protocols.

4. How are traveling quantum Gaussian wave packets created in experiments?

In experiments, traveling quantum Gaussian wave packets can be created by manipulating the state of a quantum system using techniques such as laser pulses, magnetic fields, or external potentials. These methods can be used to generate wave packets with specific shapes, sizes, and velocities, allowing researchers to study their properties and behavior.

5. Can traveling quantum Gaussian wave packets be observed directly?

No, traveling quantum Gaussian wave packets cannot be observed directly because they are a mathematical representation of a quantum particle's wave function. However, their effects can be observed indirectly through measurements and experiments, which can provide information about the particle's position, momentum, and other properties.

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