Travelling faster than the speed of light - SR

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which once graphed, shows that optimum time is to go as fast as possible.
 
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is this correct?
No.

You can use Earth distance D, then
t=D/v
t'=t/γ.

Or you use spaceship distance D', then
D'=D/γ
t'=D'/v
t=t' γ.

Either way, t'=(D/v)/γ.