Travelling wave and standing wave

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The discussion centers on the comparison between traveling waves and standing waves, specifically addressing a solution for part c, where the distance is equated to half the wavelength (λ/2 = 0.06m). It is noted that a traveling wave does not have nodes, while the λ/2 value is confirmed as correct. Participants also inquire about how to enter LaTeX on the forum, with guidance provided on accessing the LaTeX guide. The conversation highlights the importance of understanding wave properties in physics. Overall, the exchange emphasizes clarity in wave concepts and technical communication.
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Homework Statement
Travelling wave and standing wave
Relevant Equations
Travelling wave equation
1665131903406.png


I wasn't sure about my solution for part c. I said "same distance as for traveling wave ie \lambda/2=0.06m".

Also how do you enter LaTeX on this forum?
 
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Hello @Andrew Tom ,
:welcome: ##\qquad##!​

Andrew Tom said:
Homework Statement:: Travelling wave and standing wave
Relevant Equations:: Travelling wave equation

same distance as for traveling wave
A traveling wave has no nodes...

But the ##\lambda\over 2## is the correct answer.

At the lower left of the edit screen there is a link to the ##\LaTeX## guide:
1665134897933.png


##\ ##
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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