- #1
Henry365
- 3
- 0
Homework Statement
What I want to show is this:
∫|x+y| ≤ ∫|x| + ∫|y|
Homework Equations
|x+y| ≤ |x| + |y|
The Attempt at a Solution
So I thought if I used the triangle inequality I could get to something along the lines of:
Lets g belong to the real numbers
∫|x+y| = ∫|x+g-g+y|≤ ∫|x+g| + |y-g|= ∫|x+g| + ∫|y-g|
As g belongs to the reals it can be zero meaning ∫|x+y| ≤ ∫|x| + ∫|y|.
Now the problem with this is that is uses the triangle inequality and I have no idea if the triangle inequality works this way, and if it does I need to prove it, and I have no idea about where to start that from.