Triangle Inequality Proof Using Euclidean Geometry

  • Thread starter Thread starter ilaneden
  • Start date Start date
  • Tags Tags
    Euclidean
Click For Summary
The discussion focuses on proving the triangle inequality using Euclidean geometry by establishing that for any point S inside triangle ABC, the sum of distances from S to the triangle's vertices is greater than or equal to twice the sum of the perpendicular distances from S to the triangle's sides. Key steps include demonstrating that the length QR is greater than or equal to the segment P1P2 and showing the similarity between triangles PRP1 and SBR. This proof is associated with the Erdős inequality, highlighting its significance in geometric analysis. The approach emphasizes the use of geometric properties and relationships to derive the inequality. The proof reinforces foundational concepts in Euclidean geometry.
ilaneden
Messages
1
Reaction score
0
proof the following using only euclidean geometry:
Let S be any point inside a triangle ABC and let SP; SQ; SR be
perpendicular to the sides BC;CA;AB respectively, then
SA + SB + SC >= 2 (SP + SQ + SR)
Hint: Set P1; P2 be the feet of the perpendiculars from R and Q upon
BC. Prove fir st that (i) QR >= P1P2 and (ii) PRP1 and SBR are
similar triangles.
 
Physics news on Phys.org
This is a standard inequality , named after Erdo:s.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 18 ·
Replies
18
Views
5K
Replies
1
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
5K
Replies
8
Views
6K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K