Triangle Problem: Calculate Perpendicular Bisector

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Homework Help Overview

The discussion revolves around a geometry problem involving a triangle defined by its vertices A(6,-15), B(22,17), and C(24,11). The original poster seeks to find the equation of the perpendicular bisector of one side of the triangle, having identified the midpoint of side A as (14,1).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the slopes of lines and how to derive the equation of the perpendicular bisector. There are attempts to clarify the use of the midpoint and the slope in forming the equation.

Discussion Status

Some participants have provided guidance on using the slope relationship for perpendicular lines and suggested a formula for the line equation. However, there remains uncertainty among others regarding the application of these concepts, indicating that the discussion is ongoing.

Contextual Notes

There is mention of urgency in the original post, which may imply time constraints affecting the participants' engagement. The original poster's understanding of the problem setup appears to be in question, as indicated by requests for further clarification.

mr.mair
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assignment question URGENT!

I having trouble and its urgent some one help
Triangle wit the vertices A(6,-15)B(22,17)and C(24,11)

-midpoint of side A = (14,1)

Question

1.Calculate the equation of the line that is perpindicular bisector of the side triangle.
 
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Use the fact that [tex]m_{2} = -\frac{1}{m_{1}}[/tex] for a perpendicular line.
 
i Still do not get it
 
Last edited:
but how do i figure out the equation of the line
 
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The slope of [tex]AB[/tex] is [tex]2[/tex]. So the slope of the perpendicular bisector is [tex]-\frac{1}{2}[/tex].

So use the equation [tex]y-y_{1} = m(x-x_{1})[/tex].

So [tex]y - 1 = -\frac{1}{2}( x-14)[/tex]
 
Last edited:

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