Triangle with inscribed circle

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The discussion revolves around proving that for a point P inside triangle ABC with an inscribed circle of radius greater than 1, at least one of the distances PA, PB, or PC must be greater than 2. Participants express difficulty in approaching the problem and seek guidance on how to start. Suggestions include exploring formulas for minimum distances and comparing triangle areas to the inscribed circle's area. However, one participant feels the provided hints may not be applicable to their specific geometry task. The conversation highlights the challenge of tackling geometric proofs involving inscribed circles and distances.
klawesyn28
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P is a point inside triangle ABC. In the triangle there is inscribed
circle which radius is greater than 1. Prove that PA>2, PB>2 or PC>2.


I don't know how to solve it. Could anybody help me?
 
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Did you at least start the problem? If so then post what you have and we will help you from there.
 
Yes I started with this problem and then I don't know how to prove that when PA<=2, PB<=2, PC<=2, the circumradius is smaller than 2. P is point inside the triangle.
 
klawesyn28 said:
P is a point inside triangle ABC. In the triangle there is inscribed
circle which radius is greater than 1. Prove that PA>2, PB>2 or PC>2.
I don't know how to solve it. Could anybody help me?

This is one of those cases where the first step can be tough. You haven't said what kind of class this is for and so it's hard for us to figure out what kind of direction you're supposed to go in.

With that, here are some things you might think about.

(a) It would be really handy if you had a formula for the minimum that you could differentiate. It might be useful for you to know that:

min(A,B) = (|A+B| - |A-B|)/2

(b) Do you think you could do something with the area formula for a triangle as compared to the area formula for the circle? Can you write an area formula that is defined around the point P? Perhaps the areas of the three triangles PAB, PBC, PCA?

Carl
 
It's task from russian books with task from geometry. I don't see how your hints can help me.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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