fonseh
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The author doesn't. This sine appears in the calculation of the area of the triangular shaftfonseh said:Homework Statement
for the circular cross section shaft , why we need to put an sin60 as to get the area ?
Nothing ?Homework Equations
That's not an attempt at solution. Where do you see this value ? I don't even see it appearing anywhere. All I see is ##\pi c^2## which is a reasonable expression for the area of a circle with radius ##c##.The Attempt at a Solution
why the area shouldn't be pi(0.004) ^2 only ?
The author is calculating the area of the equilateral[/color] triangle, using ½×base×heightfonseh said:why we need to put an sin60 as to get the area ?