Triangular shaft change to circular shaft

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fonseh
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Homework Statement


for the circular cross section shaft , why we need to put an sin60 as to get the area ?

Homework Equations

The Attempt at a Solution


why the area shouldn't be pi(0.004) ^2 only ?
 

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fonseh said:

Homework Statement


for the circular cross section shaft , why we need to put an sin60 as to get the area ?
The author doesn't. This sine appears in the calculation of the area of the triangular shaft

Homework Equations

Nothing ?

The Attempt at a Solution


why the area shouldn't be pi(0.004) ^2 only ?
That's not an attempt at solution. Where do you see this value ? I don't even see it appearing anywhere. All I see is ##\pi c^2## which is a reasonable expression for the area of a circle with radius ##c##.
 
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fonseh said:
why we need to put an sin60 as to get the area ?
The author is calculating the area of the equilateral[/color] triangle, using ½×base×height

He then equates this area to that of a circle of radius c and is able to calculate the value of c.

 
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