Tricky Problem (at least for me)

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SUMMARY

The final velocity can be calculated using the equation v_{f,x}^2 = v_{i,x}^2 + 2 a_x (x_f-x_i). Given an initial velocity of 0 m/s, an acceleration of 0.76 m/s², and a distance of 2 meters, the final velocity is 1.1 m/s. To find the net force (F(net)), use the formula F(net) = m*a, where the mass is 5 kg and the acceleration can be derived from the final velocity over the time of 5 seconds. The force of friction is calculated as F_friction = μ * N, where μ is 0.15 and N is the normal force of 49 N, resulting in a friction force of -7.35 N.

PREREQUISITES
  • Understanding of kinematic equations, specifically v_{f,x}^2 = v_{i,x}^2 + 2 a_x (x_f-x_i)
  • Knowledge of Newton's second law, F = m*a
  • Familiarity with the concept of friction and the coefficient of kinetic friction (μ)
  • Basic understanding of forces including normal force and gravitational force
NEXT STEPS
  • Study kinematic equations in-depth, focusing on their applications in physics problems
  • Learn about Newton's laws of motion, particularly the implications of F = m*a
  • Research the principles of friction, including static and kinetic friction coefficients
  • Explore practical examples of calculating net force in various physical scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding motion and forces, particularly in the context of kinematics and dynamics.

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If I have a initial velocity of 0m/s and an acceleration of .76m/s2 and a distance of 2meters what would my final velocity be?


Also I need to find F(net) I know a mu of .15 a time of 5seconds a mass of 5kg and force of gravity equals 49N an normal force equals -49N and force of friction equals -7.35N. I think I'm supposed to use the velocity found in the question above, but I'm not sure and I don't know how. How do I find F(net) with the information I have and what is the answer??

Any help would be greatly appriciated...
 
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need help said:
If I have a initial velocity of 0m/s and an acceleration of .76m/s2 and a distance of 2meters what would my final velocity be?
[itex]v_{f,x}^2 = v_{i,x}^2 + 2 a_x (x_f-x_i)[/itex] where x_f-x_i is essentially the distance traveled. have you seen this equation before?
Also I need to find F(net) I know a mu of .15 a time of 5seconds a mass of 5kg and force of gravity equals 49N an normal force equals -49N and force of friction equals -7.35N. I think I'm supposed to use the velocity found in the question above, but I'm not sure and I don't know how. How do I find F(net) with the information I have and what is the answer??

Any help would be greatly appriciated...
It

The key point is that the magnitude of the friction force is equal to the magnitude of the normal force times the coefficient of kinetic friction [itex]\mu_k[/itex]
 

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