Tricky projectile motion question

Click For Summary
SUMMARY

The discussion focuses on solving a projectile motion problem involving an enemy ship located 2500 m from a mountain peak that is 1800 m high. The ship can launch projectiles at an initial speed of 250 m/s. The key equations used include the projectile motion equations for vertical and horizontal displacement, specifically y = 250 m/s * sin(x) * t + 0.5gt² and x = 250 m/s * cos(x) * t. The solution involves determining the angles at which the projectile clears the peak and calculating the corresponding safe distances from the western shore, which is 300 m from the peak.

PREREQUISITES
  • Understanding of projectile motion equations
  • Knowledge of trigonometric functions and their applications in physics
  • Familiarity with optimization techniques in constraint problems
  • Basic knowledge of gravitational effects on projectile trajectories
NEXT STEPS
  • Study the derivation of the range formula R = v²sin(2x)/g
  • Learn about optimization techniques in physics problems
  • Explore the effects of different launch angles on projectile motion
  • Investigate the concept of "blind spots" in projectile trajectories
USEFUL FOR

Students studying physics, particularly those focusing on projectile motion, as well as educators looking for practical examples of applying mathematical concepts to real-world scenarios.

johnyk87
Messages
2
Reaction score
0

Homework Statement


An enemy ship is on the east side of a mountain island. The enemy ship has maneuvered to within 2500 m of a 1800 m high mountain peak and can shoot projectiles with an initial speed of 250 m/s. If the western shoreline is horizontally 300 m from the peak, what are the distances from the western shore at which a ship can be safe from the bombardment of the ship?


Homework Equations


y= 250m/s*sin(x)t + .5gt^2
x= 250m/s*cos(x)t

R= v^2sin(2x)/g

The Attempt at a Solution



I can set up the problem as a constraint problem. I tried to minimize the range formula subject to the constraint that the projectile will just go over the mountain peak as it passes. The reasoning for this is that I will be able to reduce the range of a shot by shooting it at a slightly higher angle that will just clear the peak. It is not a technical reason but it seems reasonable. I can set up the problem but isolating the angle in my constraint is tricky. Does anyone know of a better way to go about this problem?
 
Physics news on Phys.org
As it follows its trajectory, the projectile can clear the mountain top on its way up ( projection angle less than 45o) or on its way down (projection angle greater than 45o). So you need to find the angles for which the projectile will just barely clear the top and then find the corresponding ranges. Then look for "blind spots" on the other side.
 
Thanks kuruman. I just figured it out a little while ago. I want the angle as it is coming down. For some reason i thought that there would be more than one downward angle that corresponded to just clearing the peak. Thanks again
 

Similar threads

Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
8
Views
2K