# Trig Functions- Could anyone tell me why my working is wrong?

1. Sep 13, 2006

### ku1005

Trig Functions- Could anyone tell me why my working is wrong??

the question seems simple..although i dont know what i am doin because it is obviously wrong!!!. thnkas heaps if anyone can help..

solve
2cosx-(sqrt(3))cosx sinx = 0 for (-pie<=x<=pie)

what i was doin is dividing through by cos x, therefore i obtain:

2-(sqrt(3))sinx= 0

however this statement is flawed!!! since no value exists for sin x= 2/(sqrt(3))

?????it seems simple.. so wat am i doing wrong!!1

2. Sep 13, 2006

### stunner5000pt

if you copied the question right then yes sin x = 2/srqt3 is not possible

however you CAN find answer for the cosine part
cos x = 0 what values of x will do?

3. Sep 14, 2006

### ku1005

yep got it now...instead i just did the follwing
=
cosx(2-(sqrt(3))sinx)=0
therfore either cosx= 0 (as u stated above) or the other applies...which isnlt possible...so yeah obviously the answers are pie/2 and -pie/2