Trignometric Polynomial complex form

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SUMMARY

The discussion focuses on the derivation of the trigonometric polynomial complex form using Fourier transforms. The user references Euler's formula, specifically the relationships \(\cos(nx) = \frac{e^{inx} + e^{-inx}}{2}\) and \(\sin(nx) = \frac{e^{inx} - e^{-inx}}{2i}\). The key conclusion is that by substituting these identities into the series and rearranging, one can achieve the desired complex form of the trigonometric polynomial.

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  • Understanding of Fourier transforms
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phillyj
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Hi,
I'm trying to learn Fourier transforms by myself. I'm a bit confused about how the trignometric polynomial complex form was derived. I'm referring to this:

http://en.wikipedia.org/wiki/Trigonometric_polynomial

Now, I haven't taken complex analysis so I only know the basics. I used Euler's formula and got that far but I'm not sure what to do next.

Thanks
 
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Substitute

[tex]\cos(nx)=\frac{e^{inx}+e^{-inx}}{2}, ~\sin(nx)=\frac{e^{inx}-e^{-inx}}{2i}[/tex]

in the series and rearrange everything. This should give you the required form.
 

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