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## Main Question or Discussion Point

Given a trig equation, like:

**sin(x)² + cos(x)² = 1²**or**sin(x) = 1/csc(x)**, exist a correspondent inverse:**arcsin(x) + arccos(x) = π/2**and**arcsin(x) = arccsc(1/x)**, respectively. Thus, given an any trigonometric equation, how find its correspondent inverse?